A plano-convex lens is made of glass with a r | vedclass

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(C) The focal length $f$ of a lens is given by the Lens Maker's Formula:$\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$For a pl

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$2R$

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(C) The focal length $f$ of a lens is given by the Lens Maker's Formula:$\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$For a plano-convex lens,one surface is convex $(R_1 = R)$ and the other is plane $(R_2 = \infty)$.Substituting these values into the formula:$\frac{1}{f} = (1.5 - 1) \left( \frac{1}{R} - \frac{1}{\infty} \right)$$\frac{1}{f} = (0.5) \left( \frac{1}{R} - 0 \right)$$\frac{1}{f} = \frac{0.5}{R} = \frac{1}{2R}$Therefore,$f = 2R$.

$A$ plano-convex lens is made of glass with a refractive index of $1.5$. The radius of curvature of its convex surface is $R$. What is its focal length?

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