A planet moving along an elliptical orbit is closest to the sun at a distance $r_1$ and farthest away at a distance of $r_2$. If $v_1$ and $v_2$ are the linear velocities at these points respectively, then the ratio $\frac{v_1}{v_2}$ is
$\frac{r_2}{r_1}$
$\left(\frac{r_2}{r_1}\right)^2$
$\frac{r_1}{r_2}$
$\left(\frac{r_1}{r_2}\right)^2$
The time period of a satellite revolving around earth in a given orbit is $7 \,hours$. If the radius of orbit is increased to three times its previous value, then approximate new time period of the satellite will be ...... $hours$
Earth is revolving around the sun if the distance of the Earth from the Sun is reduced to $\frac{1}{4}^{th}$ of the present distance then the present day length reduced by
A spherical asteroid having the same density as that of earth is floating in free space. A small pebble is revolving around the asteroid under the influence of gravity near the surface of the asteroid. What is the approximate time period of the pebble?
A binary star system consists of two stars one of which has double the mass of the other. The stars rotate about their common centre of mass :-
Every planet revolves around the sun in an elliptical orbit :
$A.$ The force acting on a planet is inversely proportional to square of distance from sun.
$B.$ Force acting on planet is inversely proportional to product of the masses of the planet and the sun
$C.$ The centripetal force acting on the planet is directed away from the sun.
$D.$ The square of time period of revolution of planet around sun is directly proportional to cube of semi-major axis of elliptical orbit.
Choose the correct answer from the options given below :