A planet moves around the sun. At a given point $P$, it is closest from the sun at a distance ${d_1}$ and has a speed ${v_1}$. At another point $ Q$, when it is farthest from the sun at a distance ${d_2}$, its speed will be
$\frac{{d_1^2{v_1}}}{{d_2^2}}$
$\frac{{{d_2}{v_1}}}{{{d_1}}}$
$\frac{{{d_1}{v_1}}}{{{d_2}}}$
$\frac{{d_2^2{v_1}}}{{d_1^2}}$
Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e. $F \propto {1\over r^3}$, but still remaining a central force. Then
A geostationary satellite is at a height $h$ above the surface of earth. If earth radius is $R$
A satellite is in a circular equatorial orbit of radius $7000\,km$ around the Earth. If it is transferred to a circular orbit of double the radius then its angular momentum will be
Consider a planet moving around a star in an elliptical orbit with period $T$. The area of the elliptical orbit is proportional to ...........
Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
$Assertion$ $(A)$ : The angular speed of the moon in its orbit about the earth is more than the angular speed of the earth in its orbit about the sun.
$Reason$ $(R)$: The moon takes less time to move around the earth than the time taken by the earth to move around the sun.
In the light of the above statements, choose the most appropriate answer from the options given below: