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(D) $1$. In an elliptical orbit,the planet's distance from the sun changes,causing the speed to vary. Therefore,kinetic energy $T$ is not conserved.$2

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$E$ is always negative

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(D) $1$. In an elliptical orbit,the planet's distance from the sun changes,causing the speed to vary. Therefore,kinetic energy $T$ is not conserved.$2$. Gravitational potential energy $V$ is defined as $V = -GMm/r$,which is always negative for bound states.$3$. Angular momentum $L$ is conserved in magnitude and direction because the gravitational force is a central force,meaning the torque $	au = r 	imes F = 0$. Since the motion is confined to a plane,the direction of the angular momentum vector remains constant.$4$. For a bound orbit (elliptical),the total mechanical energy $E = T + V$ is always negative,representing the energy required to escape the gravitational field.

$A$. Potential energy of satellite	$I$. Positive
$B$. Total energy of satellite	$II$. Negative
$C$. Kinetic energy of satellite	$III$. Zero
$D$. Gravitational potential energy of satellite at infinity	$IV$. Infinity

$A$ planet is moving in an elliptical orbit around the sun. If $T, V, E$,and $L$ stand respectively for its kinetic energy,gravitational potential energy,total energy,and magnitude of angular momentum about the centre of force,which of the following is correct?

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Match the following columns.
$A$. Potential energy of satellite $I$. Positive
$B$. Total energy of satellite $II$. Negative
$C$. Kinetic energy of satellite $III$. Zero
$D$. Gravitational potential energy of satellite at infinity $IV$. Infinity

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