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(D) The number of photoelectrons emitted is directly proportional to the intensity of the incident light.Intensity $(I)$ is inversely proportional to

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Will be one-fourth in number.

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(D) The number of photoelectrons emitted is directly proportional to the intensity of the incident light.Intensity $(I)$ is inversely proportional to the square of the distance $(d)$ from the source,i.e.,$I \propto \frac{1}{d^2}$.When the distance is increased from $1 \ m$ to $2 \ m$,the intensity becomes $\frac{1}{2^2} = \frac{1}{4}$ of the initial intensity.Since the number of ejected electrons is directly proportional to the intensity,the number of ejected electrons will also become $\frac{1}{4}$ of the initial number.The energy and momentum of the ejected electrons depend on the frequency of the incident light,not on the intensity (distance). Therefore,they remain unchanged.

$A$ photocell is receiving light from a source placed at a distance of $1 \ m$. If the same source is placed at a distance of $2 \ m$,then the ejected electrons:

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