The following graph represents the variation | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) From the graph,we observe that the stopping potential $V_{0}$ is the same for curves $1$ and $2$. However,for curve $3$,the stopping potential is

Vedclass · Accepted Answer

$\gamma_{1}=\gamma_{2}$ and $I_{1} 
eq I_{2}$

Vedclass · Answer

(A) From the graph,we observe that the stopping potential $V_{0}$ is the same for curves $1$ and $2$. However,for curve $3$,the stopping potential is greater in magnitude than that for curves $1$ and $2$.We know that the stopping potential is given by the relation: $e V_{0} = E_{\max} = h \gamma - \phi_{0}$,where $\phi_{0}$ is the work function of the metal.Since $V_{0}$ is the same for curves $1$ and $2$,it implies that the incident frequencies are equal,i.e.,$\gamma_{1} = \gamma_{2}$.For curve $3$,the stopping potential is higher,which means $\gamma_{3} > \gamma_{1} = \gamma_{2}$.Regarding the saturation current,it depends on the intensity of the incident light. Curves $2$ and $3$ reach the same saturation current,meaning $I_{2} = I_{3}$,while curve $1$ has a lower saturation current,so $I_{1} Therefore,comparing the options,$\gamma_{1} = \gamma_{2}$ and $I_{1} 
eq I_{2}$ is the correct statement.

The following graph represents the variation of photocurrent with anode potential for a metal surface. Here $I_{1}, I_{2}$ and $I_{3}$ represent intensities and $\gamma_{1}, \gamma_{2}, \gamma_{3}$ represent frequencies for curves $1, 2$ and $3$ respectively,then

Similar Questions

If the intensity of incident light is increased in $PEE$,then which of the following is true?

In a dark room of photography,generally red light is used. The reason is

$A$ photocell stops emission if it is maintained at $2V$ negative potential. The energy of the most energetic photoelectron is:

Threshold frequency for a metal is $15 \times 10^{14} \,Hz$. The light of wavelength $6000 \text{ Å}$ falls on the metal surface. Which one of the following statements is correct? [velocity of light, $c = 3 \times 10^{8} \,m/s$]

The material of the cathode in a photocell is changed such that the work function of the surface changes from $W_1$ to $W_2$ $(W_2 > W_1)$. If the photocurrents emitted before and after changing the cathode surface are $I_1$ and $I_2$ respectively,and $hf > W_2$,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module