A person sets out to cover a distance of 12 , | vedclass

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Question

(C) Total distance $= 12 \, km$.
Total time $= 45 \, minutes = \frac{45}{60} \, hours = 0.75 \, hours$.
Distance covered $= \frac{3}{4} 	imes 12 \,

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(C) Total distance $= 12 \, km$.
Total time $= 45 \, minutes = \frac{45}{60} \, hours = 0.75 \, hours$.
Distance covered $= \frac{3}{4} 	imes 12 \, km = 9 \, km$.
Time taken $= \frac{2}{3} 	imes 45 \, minutes = 30 \, minutes = 0.5 \, hours$.
Remaining distance $= 12 \, km - 9 \, km = 3 \, km$.
Remaining time $= 45 \, minutes - 30 \, minutes = 15 \, minutes = \frac{15}{60} \, hours = 0.25 \, hours$.
Required speed $= \frac{	ext{Remaining distance}}{	ext{Remaining time}} = \frac{3 \, km}{0.25 \, h} = 12 \, km/h$.

$A$ person sets out to cover a distance of $12 \, km$ in $45 \, minutes$. If he covers $\frac{3}{4}$ of the distance in $\frac{2}{3}$ of the time,what should be his speed to cover the remaining distance in the remaining time? (in $km/h$)

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