A person purchases 8 pens for ₹ 10 and sells | vedclass

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(D) Cost price of $8$ pens $= ₹ 10$.Cost price of $1$ pen $= ₹ \frac{10}{8} = ₹ 1.25$.Selling price of $10$ pens $= ₹ 8$.Selling price of $1$ pen $= ₹

Vedclass · Accepted Answer

$36 \%$ loss

Vedclass · Answer

(D) Cost price of $8$ pens $= ₹ 10$.Cost price of $1$ pen $= ₹ \frac{10}{8} = ₹ 1.25$.Selling price of $10$ pens $= ₹ 8$.Selling price of $1$ pen $= ₹ \frac{8}{10} = ₹ 0.80$.Since the selling price is less than the cost price,there is a loss.Loss $= 	ext{Cost Price} - 	ext{Selling Price} = 1.25 - 0.80 = ₹ 0.45$.Loss percentage $= \left( \frac{	ext{Loss}}{	ext{Cost Price}} ight) 	imes 100 = \left( \frac{0.45}{1.25} ight) 	imes 100 = 36 \%$.Alternatively,using the cross-multiplication method:$	ext{Loss percentage} = \left( \frac{x^2 - y^2}{x^2} ight) 	imes 100$ where $x$ is the number of pens bought for $y$ rupees.Here,$8$ pens for $10$ rupees and $10$ pens for $8$ rupees.Loss percentage $= \frac{10^2 - 8^2}{10^2} 	imes 100 = \frac{100 - 64}{100} 	imes 100 = 36 \%$.Therefore,the loss is $36 \%$.

$A$ person purchases $8$ pens for ₹ $10$ and sells $10$ pens for ₹ $8$. How much profit or loss percentage does he make?

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