(B) Let $m$ be the mass of the person and $a$ be the acceleration of the elevator.When the elevator moves downward with an acceleration $a$,the equati

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When the elevator moves downward with constant acceleration

(B) Let $m$ be the mass of the person and $a$ be the acceleration of the elevator.When the elevator moves downward with an acceleration $a$,the equation of motion for the person is:$mg - N = ma$where $N$ is the normal reaction force (apparent weight).Rearranging the equation,we get:$N = m(g - a)$Since $N < mg$,the person experiences weight loss when the elevator accelerates downward.

Class 11 Physics Newton's Laws of Motion and Friction Apparent weight and Pseudo Force

Medium

$A$ person is standing in an elevator. In which situation does he experience weight loss?

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A
When the elevator moves upward with constant acceleration
B
When the elevator moves downward with constant acceleration
C
When the elevator moves upward with uniform velocity
D
When the elevator moves downward with uniform velocity

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Class 11

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Newton's Laws of Motion and Friction

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Apparent weight and Pseudo Force

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$A$ person is standing in an elevator. In which situation does he experience weight loss?

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Select the correct statement regarding pseudo force.

$A$ person in an elevator accelerating upwards with an acceleration of $2 \, m/s^2$ tosses a coin vertically upwards with a speed of $20 \, m/s$. After how much time will the coin fall back into his hand (in $, s$)? $(g = 10 \, m/s^2)$

Two bodies of masses $m_1$ and $m_2$ are connected by a light string which passes over a frictionless,massless pulley. If the pulley is moving upward with uniform acceleration $\frac{g}{2}$,then the tension in the string will be .........

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