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(C) Let $p$ be the probability of killing the bird,so $p = 3/4$.Let $q$ be the probability of missing the bird,so $q = 1 - p = 1 - 3/4 = 1/4$.The pers

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(C) Let $p$ be the probability of killing the bird,so $p = 3/4$.Let $q$ be the probability of missing the bird,so $q = 1 - p = 1 - 3/4 = 1/4$.The person tries $n = 5$ times.The probability that he does not kill the bird at all means he misses the bird in all $5$ attempts.This is given by the binomial probability formula for $X=0$ successes: $P(X=0) = q^n = (1/4)^5$.Calculating this,we get $P(X=0) = 1^5 / 4^5 = 1 / 1024$.Therefore,the probability that he may not kill the bird is $1/1024$.

$A$ person can kill a bird with a probability of $3/4$. He tries $5$ times. What is the probability that he may not kill the bird at all (in $/1024$)?

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