If out of 20 consecutive whole numbers two ar | vedclass

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(B) The total number of ways to choose $2$ integers from $20$ consecutive integers is given by ${}^{20}C_2 = \frac{20 	imes 19}{2} = 190$.In any set

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$\frac{10}{19}$

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(B) The total number of ways to choose $2$ integers from $20$ consecutive integers is given by ${}^{20}C_2 = \frac{20 	imes 19}{2} = 190$.In any set of $20$ consecutive integers,there are exactly $10$ even numbers and $10$ odd numbers.The sum of two numbers is odd if and only if one number is even and the other is odd.The number of ways to choose one even number from $10$ and one odd number from $10$ is ${}^{10}C_1 	imes {}^{10}C_1 = 10 	imes 10 = 100$.Therefore,the required probability is $\frac{100}{190} = \frac{10}{19}$.

If out of $20$ consecutive whole numbers two are chosen at random,then the probability that their sum is odd,is

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