$A$ pendulum is executing simple harmonic motion and its maximum kinetic energy is $K_1$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same angular amplitude as in the first case,its maximum kinetic energy is $K_2$,then:

  • A
    $K_2 = 2K_1$
  • B
    $K_2 = \frac{K_1}{2}$
  • C
    $K_2 = \frac{K_1}{4}$
  • D
    $K_2 = K_1$

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