A passenger buys 5 tickets for Ahmadabad to N | vedclass

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Question

(A) Let the cost of a ticket from Ahmadabad to Nadiad be Rs. $x$ and the cost of a ticket from Ahmadabad to Vadodara be Rs. $y$.According to the probl

Vedclass · Accepted Answer

Cost of ticket for Ahmadabad to Nadiad is Rs. $50$ and for Ahmadabad to Vadodara is Rs. $80$.

Vedclass · Answer

(A) Let the cost of a ticket from Ahmadabad to Nadiad be Rs. $x$ and the cost of a ticket from Ahmadabad to Vadodara be Rs. $y$.According to the problem,we have two equations:$1) 5x + 10y = 1050$Dividing by $5$,we get: $x + 2y = 210$$2) x + y = 130$Subtracting equation $(2)$ from equation $(1)$:$(x + 2y) - (x + y) = 210 - 130$$y = 80$Substituting $y = 80$ into equation $(2)$:$x + 80 = 130$$x = 130 - 80 = 50$Therefore,the cost of a ticket from Ahmadabad to Nadiad is Rs. $50$ and the cost of a ticket from Ahmadabad to Vadodara is Rs. $80$.

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