A particle of mass m = 1.67 times 10^{-27} , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When a charged particle enters a uniform magnetic field perpendicular to its velocity,it follows a circular path. Given: $m = 1.67 	imes 10^{-27}

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) When a charged particle enters a uniform magnetic field perpendicular to its velocity,it follows a circular path. Given: $m = 1.67 	imes 10^{-27} \, kg$,$q = 1.6 	imes 10^{-19} \, C$,$v = 10^7 \, m/s$,and $B = 1 \, T$. The radius of the circular path is given by $R = \frac{mv}{qB}$. Substituting the values: $R = \frac{(1.67 	imes 10^{-27}) 	imes (10^7)}{(1.6 	imes 10^{-19}) 	imes 1} \approx 0.104 \, m = 10.4 \, cm$. From the geometry of the circular path in the magnetic field,the angle of incidence at point $C$ is $45^\circ$ with the boundary. The angle between the velocity vector and the normal to the boundary is $90^\circ - 45^\circ = 45^\circ$. Due to the symmetry of the circular arc,the angle of emergence at point $D$ with the boundary will also be $45^\circ$. Therefore,$	heta = 45^\circ$.

Similar Questions

$A$ beam of well-collimated cathode rays travelling with a speed of $5 \times 10^6 \, m/s$ enters a region of mutually perpendicular electric and magnetic fields and emerges undeviated from this region. If $|B| = 0.02 \, T$,the magnitude of the electric field is:

$A$ monoenergetic $(18 \;keV)$ electron beam initially in the horizontal direction is subjected to a horizontal magnetic field of $0.04 \;G$ normal to the initial direction. Estimate the up or down deflection of the beam over a distance of $30 \;cm$ $(m_{e} = 9.11 \times 10^{-31} \;kg)$.

$A$ proton and an $\alpha$-particle enter a magnetic field perpendicularly with the same velocity. If the proton takes $25 \mu \text{sec}$ to complete $5$ revolutions,what is the time period of the $\alpha$-particle in $\mu \text{sec}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module