A particle of mass 10 ,g is undergoing S.H.M. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Mass $m = 10 \,g = 0.01 \,kg$,Amplitude $A = 10 \,cm = 0.1 \,m$,Period $T = 0.1 \,s$.The angular frequency $\omega$ is given by $\omega = \

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) Given: Mass $m = 10 \,g = 0.01 \,kg$,Amplitude $A = 10 \,cm = 0.1 \,m$,Period $T = 0.1 \,s$.The angular frequency $\omega$ is given by $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.1} = 20\pi \,rad/s$.The maximum acceleration in $S.H.M.$ is $a_{	ext{max}} = \omega^2 A$.The maximum force is $F_{	ext{max}} = m \cdot a_{	ext{max}} = m \omega^2 A$.Substituting the values: $F_{	ext{max}} = 0.01 	imes (20\pi)^2 	imes 0.1$.$F_{	ext{max}} = 0.001 	imes 400 \pi^2 = 0.4 \pi^2$.Using $\pi^2 \approx 9.87$,$F_{	ext{max}} \approx 0.4 	imes 9.87 = 3.948 \,N$.Rounding to the nearest integer,$F_{	ext{max}} \approx 4 \,N$.

$A$ particle of mass $10 \,g$ is undergoing $S.H.M.$ with an amplitude of $10 \,cm$ and a period of $0.1 \,s$. The maximum value of the force on the particle is about ............ $N$.

Similar Questions

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is

$A$ body is oscillating in simple harmonic motion according to the equation $x = 6 \cos \left(2 \pi t + \frac{\pi}{3}\right) \ m$. The magnitude of the acceleration (in $m/s^2$) of the body at $t = 1 \ s$ is:

The average acceleration of a particle performing $SHM$ over one complete oscillation is:

What is the force constant of a particle executing $SHM$?

$A$ book is resting on a shelf that is undergoing vertical simple harmonic oscillations with an amplitude of $2.5 \,cm$. What is the minimum frequency of oscillation of the shelf for which the book will lose contact with the shelf (in $,Hz$)? (Assume that $g = 10 \,m/s^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module