A particle of mass m moving with velocity u m | vedclass

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(B) In an elastic one-dimensional collision between two particles of equal mass, the particles exchange their velocities. The particle initially movin

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$2mu/T$

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(B) In an elastic one-dimensional collision between two particles of equal mass, the particles exchange their velocities. The particle initially moving with velocity $u$ comes to rest, and the stationary particle starts moving with velocity $u$.The change in momentum of the first particle is $\Delta p = m(0 - u) = -mu$. The magnitude of the change in momentum is $|\Delta p| = mu$.The impulse imparted to the particle is equal to the area under the force-time graph. The graph is a triangle with base $T$ and height $F_0$.Impulse $J = 	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes T 	imes F_0$.Since Impulse is equal to the change in momentum, we have:$\frac{1}{2} F_0 T = mu$Solving for $F_0$:$F_0 = \frac{2mu}{T}$

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