A particle of mass M is situated at the centr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total gravitational potential $V$ at a point $P$ inside the shell is the sum of the potential due to the particle at the centre and the potent

Vedclass · Accepted Answer

$\frac{-3GM}{a}$

Vedclass · Answer

(C) The total gravitational potential $V$ at a point $P$ inside the shell is the sum of the potential due to the particle at the centre and the potential due to the spherical shell.$1$. The potential due to the particle of mass $M$ at a distance $r = \frac{a}{2}$ is $V_{particle} = \frac{-GM}{r} = \frac{-GM}{a/2} = \frac{-2GM}{a}$.$2$. The potential due to a spherical shell of mass $M$ and radius $a$ at any point inside it is constant and equal to the potential at its surface,which is $V_{shell} = \frac{-GM}{a}$.$3$. The total potential at point $P$ is $V = V_{particle} + V_{shell} = \frac{-2GM}{a} + \frac{-GM}{a} = \frac{-3GM}{a}$.

$A$ particle of mass $M$ is situated at the centre of a spherical shell of mass $M$ and radius $a$. The gravitational potential at a point situated at a distance of $\frac{a}{2}$ from the centre will be:

Similar Questions

If $x-y+1=0$ meets the circle $x^2+y^2+y-1=0$ at $A$ and $B$,then the equation of the circle with $AB$ as diameter is

Diffraction effects are easier to notice in the case of sound waves than in the case of light waves because

Which one of the following statements is not correct?

Cyclic photophosphorylation results in the formation of:

What is meant by $Tin$ plague?

Vedclass Test Series

Exam Paper Generator

Online Exam Module