A particle is projected in air at some angle to the horizontal, moves along parabola as shown in figure where $x$ and $y$ indicate horizontal and vertical directions respectively. Shown in the diagram, direction of velocity and acceleration at points $A, \,B$ and $C$.
A particle is projected in air at some angle to the horizontal, moves along parabola as shown in figure where $x$ and $y$ indicate horizontal and vertical directions respectively. Shown in the diagram, direction of velocity and acceleration at points $A, \,B$ and $C$.
$v_{x}=\text { Horizontal component of velocity }=v \cos \theta=\text { constant }$
$v_{y}=\text { Vertical component of velocity }=v \sin \theta$
Velocity will always be tangential to the curve in the direction of motion and acceleration is always vertically downward and is equal to $\mathrm{g}$.
Similar Questions
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