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(B) Given the formulas: $R = \frac{u^2 \sin 2	heta}{g}$,$H = \frac{u^2 \sin^2 	heta}{2g}$,and $T = \frac{2u \sin 	heta}{g}$.Since $u$ is constant,w

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$R$ will first increase then decrease while $H$ and $T$ both will increase

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(B) Given the formulas: $R = \frac{u^2 \sin 2	heta}{g}$,$H = \frac{u^2 \sin^2 	heta}{2g}$,and $T = \frac{2u \sin 	heta}{g}$.Since $u$ is constant,we analyze the trigonometric functions as $	heta$ varies from $30^o$ to $60^o$.For $R$: The term $\sin 2	heta$ varies from $\sin 60^o = \frac{\sqrt{3}}{2} \approx 0.866$ to $\sin 120^o = \frac{\sqrt{3}}{2} \approx 0.866$,passing through $\sin 90^o = 1$ at $	heta = 45^o$. Thus,$R$ increases until $45^o$ and then decreases.For $H$: The term $\sin^2 	heta$ increases monotonically as $	heta$ increases from $30^o$ to $60^o$ (since $\sin 30^o = 0.5$ and $\sin 60^o \approx 0.866$). Thus,$H$ increases.For $T$: The term $\sin 	heta$ increases monotonically as $	heta$ increases from $30^o$ to $60^o$. Thus,$T$ increases.Therefore,$R$ first increases then decreases,while $H$ and $T$ both increase.

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