The range of a projectile for a given initial | vedclass

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Question

(A) The horizontal range $R$ of a projectile is given by the formula $R = \frac{u^2 \sin(2	heta)}{g}$,where $u$ is the initial velocity,$	heta$ is t

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$90$

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(A) The horizontal range $R$ of a projectile is given by the formula $R = \frac{u^2 \sin(2	heta)}{g}$,where $u$ is the initial velocity,$	heta$ is the angle of projection,and $g$ is the acceleration due to gravity.To find the minimum range,we look for the angle $	heta$ that makes $\sin(2	heta)$ minimum.The range $R$ is minimum when $\sin(2	heta) = 0$,which occurs at $2	heta = 0^\circ$ or $2	heta = 180^\circ$.For $2	heta = 180^\circ$,we get $	heta = 90^\circ$.At $	heta = 90^\circ$,the projectile is thrown vertically upwards,and it returns to the point of projection,resulting in a horizontal range of $R = 0$.

The range of a projectile for a given initial velocity is maximum when the angle of projection is $45^\circ$. The range will be minimum,if the angle of projection is ......... $^\circ$.

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