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(D) The angular momentum $L$ of a particle about a point is given by the vector product $L = r 	imes p$,where $r$ is the position vector of the parti

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Remains zero

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(D) The angular momentum $L$ of a particle about a point is given by the vector product $L = r 	imes p$,where $r$ is the position vector of the particle relative to the point and $p = mv$ is the linear momentum.Since the particle is moving along a straight line,the position vector $r$ and the velocity vector $v$ (and thus the momentum vector $p$) are collinear.For any two vectors that are collinear,the cross product is zero.Therefore,$L = r 	imes p = |r||p| \sin(0^\circ) = 0$.Since the angular momentum is zero at all times,it remains zero regardless of the change in speed of the particle.

$A$ particle is moving along a straight line with increasing speed. Its angular momentum about a fixed point on this line ............

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