A particle has initial velocity (3hat i + 4ha | vedclass

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Question

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,\,\,\,Here,\
Initial\,velocity,\,\overline u  = 3\hat i + 4\hat j\
Acceleration,\,\overline a  =

Vedclass · Accepted Answer

$7$ $\sqrt 2 $ units

Vedclass · Answer

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,\,\,\,Here,\
Initial\,velocity,\,\overline u  = 3\hat i + 4\hat j\
Acceleration,\,\overline a  = 0.4\hat i + 0.3\hat j\
Time\,,\,t = 10\,s\
Let\,\overline v \,be\,velocity\,of\,a\,particle\,\
after\,10\,s.
\end{array}$

$\begin{array}{l}
{m{Using,}}\,\overline v \, = \overline u  + \,\overline a t\
	herefore \,\,\,\overline v  = \left( {3\hat i + 4\hat j} ight) + \left( {0.4\hat i + 0.3\hat j} ight)\left( {10} ight)\
\,\,\,\,\,\,\,\,\, = \,3\hat i + 4\hat j + 4\hat i + 3\hat j = 7\hat i + 7\hat j\
Speed\,of\,the\,particle\,after\,10\,s = \left| {\overline v } ight|\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \sqrt {{{\left( 7 ight)}^2} + {{\left( 7 ight)}^2}}  = 7\sqrt 2 \,units
\end{array}$

A particle has initial velocity $(3\hat i + 4\hat j$$ ) $ and has acceleration $(0.4\,\hat i + 0.3\,\hat j)$ . Its speed after $10\,s$ is

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