A particle A has charge + q and a particle B | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) Using $v = \sqrt {\frac{{2QV}}{m}} $ $==>$ $v \propto \sqrt Q $ $==>$ $\frac{{{v_A}}}{{{v_B}}} = \sqrt {\frac{{{Q_A}}}{{{Q_B}}}} = \sqrt {\f

Vedclass · Accepted Answer

$1:2$

Vedclass · Answer

(b) Using $v = \sqrt {\frac{{2QV}}{m}} $ $==>$ $v \propto \sqrt Q $ $==>$ $\frac{{{v_A}}}{{{v_B}}} = \sqrt {\frac{{{Q_A}}}{{{Q_B}}}} = \sqrt {\frac{q}{{4q}}} = \frac{1}{2}$

A particle $A$ has charge $ + q$ and a particle $B$ has charge $ + \,4q$ with each of them having the same mass $m$. When allowed to fall from rest through the same electric potential difference, the ratio of their speed $\frac{{{v_A}}}{{{v_B}}}$ will become

Similar Questions

When a negative charge is taken at a height from earth's surface, then its potential energy

Derive the formula for the electric potential energy of system of two charges.

A point chargr $Q$ is fixed A small charge $q$ and mass $m$ is given a velocity $v_0$ from infinity & perpendicular distance $r_0$ as shown. If distance of closest approach is $r_0/2$. The value of $q$ is [Given $mv_0^2 = \frac{{{Q^2}}}{{4\pi { \in _0}\,{r_0}}}$]

A point charge is surrounded symmetrically by six identical charges at distance $r$ as shown in the figure. How much work is done by the forces of electrostatic repulsion when the point charge $q$ at the centre is removed at infinity

An alpha particle is accelerated through a potential difference of ${10^6}\,volt$. Its kinetic energy will be......$MeV$