(N/A) Given: Charge $q = 34.8\,kC = 3.48 \times 10^4\,C$. Coulomb's constant $k = 9 \times 10^9\,N\cdot m^2/C^2$.
The force between two point charges is given by $F = \frac{k|q|^2}{r^2}$.
$(i)$ For $r_1 = 1\,cm = 10^{-2}\,m$:
$F_1 = \frac{9 \times 10^9 \times (3.48 \times 10^4)^2}{(10^{-2})^2} = \frac{9 \times 10^9 \times 12.11 \times 10^8}{10^{-4}} = 1.09 \times 10^{23}\,N$.
$(ii)$ For $r_2 = 100\,m$:
$F_2 = \frac{9 \times 10^9 \times (3.48 \times 10^4)^2}{(100)^2} = \frac{109 \times 10^{21}}{10^4} = 1.09 \times 10^{15}\,N$.
$(iii)$ For $r_3 = 10^6\,m$:
$F_3 = \frac{9 \times 10^9 \times (3.48 \times 10^4)^2}{(10^6)^2} = \frac{109 \times 10^{21}}{10^{12}} = 1.09 \times 10^7\,N$.
Conclusion: The calculated forces are extremely large. This indicates that it is nearly impossible to separate the positive and negative charges in a neutral object,which explains why matter is generally electrically neutral.