sqrt{52 times 27 div 6 + 26 - 4} = ? | vedclass

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Question

(D) To solve the expression $\sqrt{52 	imes 27 \div 6 + 26 - 4}$,we follow the order of operations $(BODMAS)$.First,perform the division: $27 \div 6

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(D) To solve the expression $\sqrt{52 	imes 27 \div 6 + 26 - 4}$,we follow the order of operations $(BODMAS)$.First,perform the division: $27 \div 6 = 4.5$.Next,perform the multiplication: $52 	imes 4.5 = 234$.Then,perform the addition and subtraction: $234 + 26 - 4 = 256$.Finally,calculate the square root: $\sqrt{256} = 16$.

$\sqrt{52 \times 27 \div 6 + 26 - 4} = ?$

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