$A$ moving coil galvanometer has a resistance of $50\,\Omega$ and gives full-scale deflection for $10\,mA$. How could it be converted into an ammeter with a full-scale deflection for $1\,A$?

$A$ galvanometer coil has a resistance of $50 \Omega$ and the meter shows full scale deflection for a current of $5 \text{ mA}$. This galvanometer is converted into a voltmeter of range $0-20 \text{ V}$ by connecting:

$A$ galvanometer of resistance $50 \Omega$ is connected to a battery of $3 \text{ V}$ along with a resistance of $2950 \Omega$ in series. $A$ full-scale deflection of $30$ divisions is obtained in the galvanometer. In order to reduce this deflection to $20$ divisions,the resistance in series should be: (in $Omega$)

An ammeter of $5\,\Omega$ resistance can read $5\,mA$. If it is to be used to read $100\,V$,how much resistance is to be connected in series? (in $\Omega$)

Two tangent galvanometers $A$ and $B$ are identical except in their number of turns. They are connected in series. On passing a current through them,deflections of $60^{\circ}$ and $30^{\circ}$ are produced. The ratio of the number of turns in $A$ and $B$ is

The range of a voltmeter of resistance $G \ \Omega$ is $V$ volt. The resistance required to be connected in series with it in order to convert it into a voltmeter of range $nV$ volt, will be