A galvanometer coil has a resistance of 50 Om | vedclass

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(A) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer coil.The formula for the series

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$3950 \Omega$ in series with galvanometer

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(A) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer coil.The formula for the series resistance is given by $R = \frac{V}{I_g} - G$.Given values are:Voltage range $V = 20 	ext{ V}$Full scale deflection current $I_g = 5 	ext{ mA} = 5 	imes 10^{-3} 	ext{ A}$Galvanometer resistance $G = 50 \Omega$Substituting these values into the formula:$R = \frac{20}{5 	imes 10^{-3}} - 50$$R = \frac{20}{0.005} - 50$$R = 4000 - 50 = 3950 \Omega$Thus,a resistance of $3950 \Omega$ must be connected in series with the galvanometer.

$A$ galvanometer coil has a resistance of $50 \Omega$ and the meter shows full scale deflection for a current of $5 \text{ mA}$. This galvanometer is converted into a voltmeter of range $0-20 \text{ V}$ by connecting:

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