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(D) The torque $	au$ acting on a current-carrying coil placed in a magnetic field is given by the formula $	au = \vec{m} 	imes \vec{B}$,where $\vec

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$NABI$

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(D) The torque $	au$ acting on a current-carrying coil placed in a magnetic field is given by the formula $	au = \vec{m} 	imes \vec{B}$,where $\vec{m}$ is the magnetic dipole moment and $\vec{B}$ is the magnetic field.For a coil with $N$ turns,area $A$,and current $I$,the magnetic moment is $m = NIA$.The magnitude of the torque is $	au = mB \sin 	heta$,where $	heta$ is the angle between the normal to the coil and the magnetic field.In a moving coil galvanometer,the magnetic field is made radial so that the plane of the coil is always parallel to the magnetic field lines. This means the angle between the normal to the coil and the magnetic field is always $90^\circ$.Therefore,$\sin 90^\circ = 1$.Substituting these values,we get $	au = (NIA)B \sin 90^\circ = NABI$.

$A$ moving coil galvanometer has $N$ number of turns in a coil of effective area $A$,and it carries a current $I$. The magnetic field $B$ is radial. The torque acting on the coil is:

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