$A$ voltmeter having a resistance of $50 \times 10^3 \, \Omega$ is used to measure the voltage in a circuit. To increase the range of measurement $3$ times,the additional series resistance required is:

The sensitivity of a galvanometer that measures current is decreased by $\frac{1}{40}$ times by using a shunt resistance of $10 \Omega$. Then,the value of the resistance of the galvanometer is (in $Omega$)

The resistance of a galvanometer is $50\,\Omega$ and it requires $2\,\mu A$ per two division deflection. The value of the shunt required in order to convert this galvanometer into an ammeter of range $5\,A$ is (The number of divisions on the galvanometer scale on one side is $30$).

In the given figure,an ammeter $A$ consists of a $240 \Omega$ coil connected in parallel to a $10 \Omega$ shunt. The reading of the ammeter is . . . . . . $mA$.

$A$ moving coil galvanometer is converted into an ammeter of range $0$ to $5 \, mA$. The galvanometer resistance is $90 \, \Omega$ and the shunt resistance has a value of $10 \, \Omega$. If there are $50$ divisions in the galvanometer-turned-ammeter on either side of zero, its current sensitivity is

If only $2 \%$ of the total current passes through an ammeter having a coil of resistance $R$,then the resistance of the shunt of the ammeter is: