A motorcycle starts from rest and accelerates | vedclass

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(B) The observer (motorcycle) is in motion and the source (siren) is at rest. The Doppler effect formula is given by $n' = n \left( \frac{v - v_O}{v}

Vedclass · Accepted Answer

$98$

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(B) The observer (motorcycle) is in motion and the source (siren) is at rest. The Doppler effect formula is given by $n' = n \left( \frac{v - v_O}{v} ight)$,where $v$ is the speed of sound and $v_O$ is the speed of the observer.Given $n' = 0.94n$,we have $0.94n = n \left( \frac{330 - v_O}{330} ight)$.Simplifying this,$0.94 	imes 330 = 330 - v_O$.$v_O = 330 - 310.2 = 19.8 \; m/s$.The motorcycle starts from rest $(u = 0)$ and accelerates at $a = 2 \; m/s^2$. Using the equation of motion $v_O^2 = u^2 + 2as$:$(19.8)^2 = 0^2 + 2 	imes 2 	imes s$.$392.04 = 4s$.$s = 98.01 \; m \approx 98 \; m$.

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