A mixture of one mole each of H_2,He and O_2 | vedclass

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(C) According to Dalton's law of partial pressure:$p_i = x_i 	imes P_T$Where $p_i$ is the partial pressure of the $i^{th}$ component,$x_i$ is the mol

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$6$

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(C) According to Dalton's law of partial pressure:$p_i = x_i 	imes P_T$Where $p_i$ is the partial pressure of the $i^{th}$ component,$x_i$ is the mole fraction of the $i^{th}$ component,and $P_T$ is the total pressure of the mixture.Given: $n_{H_2} = 1 \ mol$,$n_{He} = 1 \ mol$,$n_{O_2} = 1 \ mol$.Total moles $n_{total} = 1 + 1 + 1 = 3 \ mol$.Mole fraction of $H_2$ is $x_{H_2} = \frac{n_{H_2}}{n_{total}} = \frac{1}{3}$.Given partial pressure of $H_2$ is $p_{H_2} = 2 \ atm$.Using the formula: $2 \ atm = \frac{1}{3} 	imes P_T$.Therefore,$P_T = 2 \ atm 	imes 3 = 6 \ atm$.

$A$ mixture of one mole each of $H_2$,$He$ and $O_2$ are enclosed in a cylinder of volume $V$ at temperature $T$. If the partial pressure of $H_2$ is $2 \ atm$,the total pressure of the gases in the cylinder is $....... \ atm$

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