A sample of O_2 gas is collected over water a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Dalton's Law of Partial Pressures,the total pressure of a gas collected over water is the sum of the partial pressure of the dry gas

Vedclass · Accepted Answer

$0.96\, atm$

Vedclass · Answer

(C) According to Dalton's Law of Partial Pressures,the total pressure of a gas collected over water is the sum of the partial pressure of the dry gas and the vapour pressure of water at that temperature.$P_{	ext{total}} = P_{O_2} + P_{H_2O}$Given:$P_{	ext{total}} = 751\, mm\, Hg$$P_{H_2O} = 21\, mm\, Hg$Therefore,$P_{O_2} = P_{	ext{total}} - P_{H_2O} = 751 - 21 = 730\, mm\, Hg$.To convert this to atmospheres,we use the relation $1\, atm = 760\, mm\, Hg$:$P_{O_2} = \frac{730}{760}\, atm \approx 0.96\, atm$.

$A$ sample of $O_2$ gas is collected over water at $23\,^oC$ at a barometric pressure of $751\, mm\, Hg$ (vapour pressure of water at $23\,^oC$ is $21\, mm\, Hg$). The partial pressure of $O_2$ gas in the sample collected is

Similar Questions

The ratio $\gamma$ for inert gases is

In a closed vessel at $25 \, ^oC$ temperature,$4 \, mole$ $O_2$,$3 \, mole$ $Cl_2$,and $3 \, mole$ $N_2$ are mixed,and the total pressure is found to be $50 \, bar$. Find the partial pressure of each gas.

During the evaporation of a liquid,the temperature of the liquid ..

$A$ gaseous mixture was prepared by taking equal moles of $CO$ and $N_2$. If the total pressure of the mixture was found to be $1 \ atm$,the partial pressure of the nitrogen $(N_2)$ in the mixture is $...$ $atm$.

At $400 \ K$ temperature in a closed vessel,the $\%$ by volume of $He, Ne$,and $Ar$ are $40\%, 40\%$,and $20\%$ respectively. If the total pressure is $25 \ bar$,find the partial pressure of each gas.

Vedclass Test Series

Exam Paper Generator

Online Exam Module