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(B) In a cubic close-packed $(CCP)$ structure,the number of $O^{2-}$ ions per unit cell is $4$. The number of octahedral voids is equal to the number

Vedclass · Accepted Answer

$MnAl_{2}O_{4}$

Vedclass · Answer

(B) In a cubic close-packed $(CCP)$ structure,the number of $O^{2-}$ ions per unit cell is $4$. The number of octahedral voids is equal to the number of $O^{2-}$ ions,which is $4$. The number of tetrahedral voids is twice the number of $O^{2-}$ ions,which is $8$. Number of $Al^{3+}$ ions = $\frac{1}{2} 	imes 4 = 2$. Number of $Mn^{2+}$ ions = $\frac{1}{8} 	imes 8 = 1$. Therefore,the ratio of $Mn : Al : O$ is $1 : 2 : 4$. The chemical formula of the mineral is $MnAl_{2}O_{4}$.

$A$ mineral consists of a cubic close-packed structure formed by $O^{2-}$ ions,where half the octahedral voids are occupied by $Al^{3+}$ and one-eighth of the tetrahedral voids are occupied by $Mn^{2+}$. The chemical formula of the mineral is

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