$A$ metallic rod of length $l$ is tied to a string of length $2l$ and made to rotate with angular speed $\omega$ on a horizontal table with one end of the string fixed. If there is a vertical magnetic field $B$ in the region,the $e.m.f.$ induced across the ends of the rod is
- A$\frac{2B\omega l^2}{2}$
- B$\frac{3B\omega l^2}{2}$
- C$\frac{4B\omega l^2}{2}$
- D$\frac{5B\omega l^2}{2}$
Explore More
Similar Questions
$A$ circular coil of area $3 \times 10^{-2} \, m^2$, $900$ turns, and a resistance of $1.8 \, \Omega$ is placed with its plane perpendicular to a uniform magnetic field of $3.5 \times 10^{-5} \, T$. The current induced in the coil when it is rotated through $180^{\circ}$ in half a second is (in $ \, mA$)
$A$ simple pendulum with a bob of mass $m$ and a conducting wire of length $L$ swings under gravity through an angle $2\theta$. The Earth's magnetic field component in the direction perpendicular to the swing is $B$. The maximum potential difference induced across the pendulum is
Difficult
View SolutionThe figure shows a straight wire placed between the pole pieces of a magnet. An induced emf will be developed across the ends of the wire when it is moved towards:
$A$ constant force $F$ is applied to a conducting rod of length $l$ moving with constant speed $V$ on two parallel conducting rails connected at the ends by a resistance $R$ in a uniform magnetic field $B$,as shown. If the current flowing through the circuit is $I$,then:
Medium
View SolutionWhat is motional $emf$?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo