$A$ metal is irradiated with light of wavelength $660 \, nm$. Given that the work function of the metal is $1.0 \, eV$,the de Broglie wavelength of the ejected electron is close to

  • A
    $6.6 \times 10^{-7} \, m$
  • B
    $8.9 \times 10^{-11} \, m$
  • C
    $1.3 \times 10^{-9} \, m$
  • D
    $6.6 \times 10^{13} \, m$

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$A$ body of mass $x$ $kg$ is moving with a velocity of $100$ $ms^{-1}$. Its de-Broglie wavelength is $6.62 \times 10^{-35}$ $m$. Hence,$x$ is ($h = 6.62 \times 10^{-34}$ $Js$). (in $kg$)

If the kinetic energy of an electron of mass $9.0 \times 10^{-31} \ kg$ is $8.0 \times 10^{-25} \ J$,the wavelength of this electron in $nm$ is

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