A body of mass x kg is moving with a velocity | vedclass

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(A) The de-Broglie wavelength formula is given by $\lambda = \frac{h}{mv}$.Rearranging the formula to solve for mass $m$,we get $m = \frac{h}{\lambda

Vedclass · Accepted Answer

$0.1$

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(A) The de-Broglie wavelength formula is given by $\lambda = \frac{h}{mv}$.Rearranging the formula to solve for mass $m$,we get $m = \frac{h}{\lambda v}$.Given values are $h = 6.62 	imes 10^{-34} 	ext{ } Js$,$\lambda = 6.62 	imes 10^{-35} 	ext{ } m$,and $v = 100 	ext{ } ms^{-1}$.Substituting these values into the equation:$m = \frac{6.62 	imes 10^{-34}}{6.62 	imes 10^{-35} 	imes 100}$.$m = \frac{10^{-34}}{10^{-35} 	imes 10^2} = \frac{10^{-34}}{10^{-33}} = 10^{-1} = 0.1 	ext{ } kg$.Therefore,$x = 0.1 	ext{ } kg$.

$A$ body of mass $x$ $kg$ is moving with a velocity of $100$ $ms^{-1}$. Its de-Broglie wavelength is $6.62 \times 10^{-35}$ $m$. Hence,$x$ is ($h = 6.62 \times 10^{-34}$ $Js$). (in $kg$)

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