A medicine capsule is in the shape of a cylin | vedclass

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(B) It can be observed that:Radius $(r)$ of the cylindrical part $=$ Radius $(r)$ of the hemispherical part $= \frac{	ext{Diameter of the capsule}}{2

Vedclass · Accepted Answer

$220$

Vedclass · Answer

(B) It can be observed that:Radius $(r)$ of the cylindrical part $=$ Radius $(r)$ of the hemispherical part $= \frac{	ext{Diameter of the capsule}}{2} = \frac{5}{2} \, mm = 2.5 \, mm$.Length of the cylindrical part $(h) = 	ext{Length of the entire capsule} - 2 	imes r$$= 14 \, mm - 2 	imes (2.5 \, mm) = 14 \, mm - 5 \, mm = 9 \, mm$.Surface area of the capsule $= 2 	imes 	ext{CSA of hemispherical part} + 	ext{CSA of cylindrical part}$$= 2 	imes (2 \pi r^2) + 2 \pi r h$$= 4 \pi r^2 + 2 \pi r h$$= 2 \pi r (2r + h)$$= 2 	imes \frac{22}{7} 	imes 2.5 	imes (2 	imes 2.5 + 9)$$= 2 	imes \frac{22}{7} 	imes 2.5 	imes (5 + 9)$$= 2 	imes \frac{22}{7} 	imes 2.5 	imes 14$$= 2 	imes 22 	imes 2.5 	imes 2$$= 220 \, mm^2$.

$A$ medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends (see figure). The length of the entire capsule is $14 \, mm$ and the diameter of the capsule is $5 \, mm$. Find its surface area. $\left[ \text{Use } \pi = \frac{22}{7} \right]$ (in $mm^2$)

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