A man walks on a straight road from his home | vedclass

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(B) Time taken to reach the market: $t_{1} = \frac{2.5 \; km}{5 \; km/h} = 0.5 \; h = 30 \; min$.Time taken to return home: $t_{2} = \frac{2.5 \; km}{

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) Time taken to reach the market: $t_{1} = \frac{2.5 \; km}{5 \; km/h} = 0.5 \; h = 30 \; min$.Time taken to return home: $t_{2} = \frac{2.5 \; km}{7.5 \; km/h} = \frac{1}{3} \; h \approx 20 \; min$.Total time taken for the round trip: $t_{total} = 30 \; min + 20 \; min = 50 \; min = \frac{50}{60} \; h = \frac{5}{6} \; h$.Total distance traveled: $d_{total} = 2.5 \; km + 2.5 \; km = 5 \; km$.Average speed is defined as the total distance traveled divided by the total time taken.Average speed $= \frac{	ext{Total distance}}{	ext{Total time}} = \frac{5 \; km}{5/6 \; h} = 5 	imes \frac{6}{5} \; km/h = 6 \; km/h$.

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