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(B) Let the total time taken be $T$. The person travels for the first half time $t = \frac{T}{2}$ with velocity $v_1$,so the distance covered is $s_1

Vedclass · Accepted Answer

$V = \frac{v_1 + v_2}{2}$

Vedclass · Answer

(B) Let the total time taken be $T$. The person travels for the first half time $t = \frac{T}{2}$ with velocity $v_1$,so the distance covered is $s_1 = v_1 	imes \frac{T}{2}$.The person travels for the next half time $t = \frac{T}{2}$ with velocity $v_2$,so the distance covered is $s_2 = v_2 	imes \frac{T}{2}$.The mean velocity $V$ is defined as the total displacement divided by the total time.$V = \frac{s_1 + s_2}{T} = \frac{v_1(T/2) + v_2(T/2)}{T} = \frac{(v_1 + v_2)(T/2)}{T} = \frac{v_1 + v_2}{2}$.

$A$ person travels along a straight road for the first half time with a velocity $v_1$ and the next half time with a velocity $v_2$. The mean velocity $V$ of the man is

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