(D) Given: Maximum height $h = 20 \; m$,acceleration due to gravity $g = 10 \; m/s^2$.At the highest point,the final velocity $v = 0$.Using the equati

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(D) Given: Maximum height $h = 20 \; m$,acceleration due to gravity $g = 10 \; m/s^2$.At the highest point,the final velocity $v = 0$.Using the equation of motion $v^2 = u^2 - 2gh$:$0^2 = u^2 - 2 \times 10 \times 20$$u^2 = 400$$u = 20 \; m/s$.Now,the total time of flight $T$ is given by $T = \frac{2u}{g}$:$T = \frac{2 \times 20}{10} = 4 \; s$.Therefore,the initial velocity is $20 \; m/s$ and the time in the air is $4 \; s$.

Class 11 Physics Motion in Straight Line Motion Under Gravity

Medium

$A$ man throws a ball vertically upward and it rises through $20 \; m$ and returns to his hands. What was the initial velocity $(u)$ of the ball and for how much time $(T)$ it remained in the air? $[g = 10 \; m/s^2]$

A
$u = 10 \; m/s, T = 2 \; s$
B
$u = 10 \; m/s, T = 4 \; s$
C
$u = 20 \; m/s, T = 2 \; s$
D
$u = 20 \; m/s, T = 4 \; s$

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Motion in Straight Line

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Motion Under Gravity

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$A$ man throws a ball vertically upward and it rises through $20 \; m$ and returns to his hands. What was the initial velocity $(u)$ of the ball and for how much time $(T)$ it remained in the air? $[g = 10 \; m/s^2]$

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