A man swimming in a stream which flows at 1.5 | vedclass

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Question

(B) Let the speed of the swimmer in still water be $x \, km/hr$ and the speed of the stream be $y = 1.5 \, km/hr$.The speed downstream is $(x + y) \,

Vedclass · Accepted Answer

$4.5$

Vedclass · Answer

(B) Let the speed of the swimmer in still water be $x \, km/hr$ and the speed of the stream be $y = 1.5 \, km/hr$.The speed downstream is $(x + y) \, km/hr$ and the speed upstream is $(x - y) \, km/hr$.According to the problem,the distance covered downstream in a given time $t$ is twice the distance covered upstream in the same time $t$.Distance = Speed $	imes$ Time.So,$(x + y) 	imes t = 2 	imes (x - y) 	imes t$.Dividing both sides by $t$,we get $x + y = 2(x - y)$.$x + 1.5 = 2x - 3$.$x = 1.5 + 3 = 4.5 \, km/hr$.Therefore,the speed of the swimmer in still water is $4.5 \, km/hr$.

$A$ man swimming in a stream which flows at $1.5 \, km/hr$ finds that in a given time he can swim twice as far with the stream as he can against it. At what rate does he swim in still water? (in $km/hr$)

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