A man having height 6 m observes an erect im | vedclass

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(B) The magnification $m$ is given by the ratio of the height of the image $(h_i)$ to the height of the object $(h_o)$.Here,$h_i = 2 \ m$ and $h_o = 6

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(B) The magnification $m$ is given by the ratio of the height of the image $(h_i)$ to the height of the object $(h_o)$.Here,$h_i = 2 \ m$ and $h_o = 6 \ m$.Magnification $m = \frac{h_i}{h_o} = \frac{2}{6} = \frac{1}{3}$.Since the image is erect and diminished $(|m| < 1)$,the mirror must be a convex mirror. $A$ plane mirror always produces an image of the same size as the object,and a concave mirror produces a diminished erect image only when the object is placed between the pole and the focus,but it is not the standard case for general observation.

$A$ man having height $6 \ m$ observes an erect image of height $2 \ m$. The mirror used is:

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