$A$ long straight wire along the $z-$ axis carries a current $I$ in the negative $z$ direction. The magnetic field vector $\vec B$ at a point having coordinates $(x, y)$ in the $z = 0$ plane is

  • A
    $\frac{{\mu _0}I(y\hat i - x\hat j)}{{2\pi ({x^2} + {y^2})}}$
  • B
    $\frac{{\mu _0}I(x\hat i + y\hat j)}{{2\pi ({x^2} + {y^2})}}$
  • C
    $\frac{{\mu _0}I(x\hat j - y\hat i)}{{2\pi ({x^2} + {y^2})}}$
  • D
    $\frac{{\mu _0}I(x\hat i - y\hat j)}{{2\pi ({x^2} + {y^2})}}$

Explore More

Similar Questions

If $5 \cos x + 12 \cos y = 13$,then the maximum value of $5 \sin x + 12 \sin y$ is:

Regarding the molecular orbital $(MO)$ energy levels for homonuclear diatomic molecules, the $\text{INCORRECT}$ statement$(s)$ is$($are$)$
$(A)$ Bond order of $Ne _2$ is zero.
$(B)$ The highest occupied molecular orbital $\text{(HOMO)}$ of $F_2$ is $\sigma$-type.
$(C)$ Bond energy of $O _2^{+}$is smaller than the bond energy of $O _2$.
$(D)$ Bond length of $Li _2$ is larger than the bond length of $B _2$

If the position vectors of $A, B$ and $C$ are respectively $2 \hat{i}-\hat{j}+\hat{k}, \hat{i}-3 \hat{j}-5 \hat{k}$ and $3 \hat{i}-4 \hat{j}-4 \hat{k}$,then $\cos ^2 A$ is equal to

Which process of purification is represented by the following equation :
$Ti$ (Impure) $+ 2I_2$ $\xrightarrow{250 \ ^\circ C}$ $TiI_4$ $\xrightarrow{1400 \ ^\circ C}$ $Ti$ (Pure) $+ 2I_2$

Assertion : The isothermal curves intersect each other at a certain point.
Reason : The isothermal change takes place slowly,so,the isothermal curves have very little slope.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo