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Question

(A) When a charge $q$ is given to the inner cylinder of radius $r_1$, an electric field $E$ is produced in the region between the inner and outer cyli

Vedclass · Accepted Answer

a potential difference appears between the two cylinders when a charge density is given to the inner cylinder.

Vedclass · Answer

(A) When a charge $q$ is given to the inner cylinder of radius $r_1$, an electric field $E$ is produced in the region between the inner and outer cylinders $(r_1 < r < r_2)$.
According to Gauss's Law, the electric field in the region between the cylinders is $E = \frac{\lambda}{2\pi\epsilon_0 r}$, where $\lambda$ is the linear charge density.
The potential difference $V$ between the cylinders is given by $V = \int_{r_1}^{r_2} E \, dr = \frac{\lambda}{2\pi\epsilon_0} \ln\left(\frac{r_2}{r_1}ight)$.
Since $V 
eq 0$, a potential difference exists between the two cylinders when the inner cylinder is charged.
Therefore, option $A$ is correct.

$A$ long, hollow conducting cylinder is kept coaxially inside another long, hollow conducting cylinder of larger radius. Both the cylinders are initially electrically neutral. Then

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