A line passes through (2, 2) and is perpendic | vedclass

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(D) The given line is $3x + y = 3$,which can be written as $y = -3x + 3$. The slope of this line is $m_1 = -3$.The slope of a line perpendicular to th

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$4/3$

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(D) The given line is $3x + y = 3$,which can be written as $y = -3x + 3$. The slope of this line is $m_1 = -3$.The slope of a line perpendicular to this line is $m_2 = -1/m_1 = -1/(-3) = 1/3$.The equation of the line passing through $(2, 2)$ with slope $m_2 = 1/3$ is given by $y - y_1 = m_2(x - x_1)$.Substituting the values,we get $y - 2 = \frac{1}{3}(x - 2)$.Multiplying by $3$,we get $3y - 6 = x - 2$,which simplifies to $x - 3y + 4 = 0$.To find the $y$-intercept,we set $x = 0$ in the equation: $0 - 3y + 4 = 0$,which gives $3y = 4$ or $y = 4/3$.Thus,the $y$-intercept is $4/3$.

$A$ line passes through $(2, 2)$ and is perpendicular to the line $3x + y = 3$. Its $y$-intercept is

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