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(D) For a light ray incident normally on one face,the angle of incidence $i = 0^{\circ}$,which implies the angle of refraction $r_{1} = 0^{\circ}$.For

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$\frac{2}{\sqrt{3}}$

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(D) For a light ray incident normally on one face,the angle of incidence $i = 0^{\circ}$,which implies the angle of refraction $r_{1} = 0^{\circ}$.For an equilateral prism,the angle of the prism $A = 60^{\circ}$.Using the relation $A = r_{1} + r_{2}$,we get $60^{\circ} = 0^{\circ} + r_{2}$,so $r_{2} = 60^{\circ}$.The ray emerges grazingly from the other face,meaning the angle of emergence $e = 90^{\circ}$.Applying Snell's law at the second face: $\mu \sin r_{2} = 1 \sin e$.Substituting the values: $\mu \sin 60^{\circ} = \sin 90^{\circ}$.$\mu 	imes \frac{\sqrt{3}}{2} = 1$.Therefore,$\mu = \frac{2}{\sqrt{3}}$.

$A$ light ray incident normally on one face of an equilateral prism and emerges out grazingly at the other face. The refractive index of the prism is

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