A lens behaves as a converging lens in air an | vedclass

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Question

(C) The focal length of a lens in a medium is given by the Lens Maker's Formula: $\frac{1}{f} = (\frac{\mu_l}{\mu_m} - 1)(\frac{1}{R_1} - \frac{1}{R_2

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between unity and $1.33$

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(C) The focal length of a lens in a medium is given by the Lens Maker's Formula: $\frac{1}{f} = (\frac{\mu_l}{\mu_m} - 1)(\frac{1}{R_1} - \frac{1}{R_2})$.For a lens to change its nature (converging to diverging),the sign of the focal length must change when placed in water.This happens if the refractive index of the lens material $\mu_l$ lies between the refractive index of air $(\mu_a \approx 1)$ and the refractive index of water $(\mu_w \approx 1.33)$.Thus,the condition is $1 < \mu_l < 1.33$.

$A$ lens behaves as a converging lens in air and a diverging lens in water. The refractive index of the lens is

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