A jet airplane travelling at the speed of 500 | vedclass

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Question

(C) Let the velocity of the jet airplane with respect to the ground be $v_p = 500 \; km \; h^{-1}$.Let the velocity of the combustion products with re

Vedclass · Accepted Answer

$1000 \; km \; h^{-1}$

Vedclass · Answer

(C) Let the velocity of the jet airplane with respect to the ground be $v_p = 500 \; km \; h^{-1}$.Let the velocity of the combustion products with respect to the jet airplane be $v_{cp/p} = -1500 \; km \; h^{-1}$ (since they are ejected in the opposite direction to the plane's motion).The velocity of the combustion products with respect to the ground $v_{cp}$ is given by the relative velocity formula:$v_{cp/p} = v_{cp} - v_p$Substituting the values:$-1500 = v_{cp} - 500$$v_{cp} = -1500 + 500 = -1000 \; km \; h^{-1}$.The speed is the magnitude of the velocity,which is $1000 \; km \; h^{-1}$.

$A$ jet airplane travelling at the speed of $500 \; km \; h^{-1}$ ejects its products of combustion at the speed of $1500 \; km \; h^{-1}$ relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?

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