A heater is joined in parallel with a 60, W b | vedclass

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(C) In a parallel circuit,the voltage across each component remains the same as the supply voltage $(V)$.The rate of heat produced by a heater is give

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Remain the same

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(C) In a parallel circuit,the voltage across each component remains the same as the supply voltage $(V)$.The rate of heat produced by a heater is given by the formula $P = V^2 / R$,where $V$ is the voltage and $R$ is the resistance of the heater.Since the heater is connected in parallel to the mains,its voltage $V$ remains constant regardless of the bulb connected in parallel with it.Therefore,replacing the $60\, W$ bulb with a $100\, W$ bulb does not change the voltage across the heater.Consequently,the rate of heat produced by the heater remains the same.

$A$ heater is joined in parallel with a $60\, W$ bulb and connected to the mains. If the $60\, W$ bulb is replaced by a $100\, W$ bulb,will the rate of heat produced by the heater be more,less,or remain the same?

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