(C) For a $NOR$ gate, the output is high $(1)$ only when all inputs are low $(0)$. If inputs are $A$ and $B$, the output $Y = \overline{A+B}$. If $A=0

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(C) For a $NOR$ gate, the output is high $(1)$ only when all inputs are low $(0)$. If inputs are $A$ and $B$, the output $Y = \overline{A+B}$. If $A=0$ and $B=0$, then $Y = \overline{0+0} = \overline{0} = 1$. Thus, the correct gate is a $NOR$ gate. Therefore, the correct option is $C$.